What is (\partial)/(\partial y)(1-3/x+y) ?

The answer to (\partial)/(\partial y)(1-3/x+y) is 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(1-3/x+y)

\frac{\partial}{\partial y} (1 - \frac{3}{x} + y)

1

Solution steps

\frac{\partial}{\partial y} (1 - \frac{3}{x} + y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (1) - \frac{\partial}{\partial y} (\frac{3}{x}) + \frac{\partial}{\partial y} (y)

\frac{\partial}{\partial y} (1) = 0

\frac{\partial}{\partial y} (\frac{3}{x}) = 0

\frac{\partial}{\partial y} (y) = 1

= 0 - 0 + 1

Simplify

= 1

x \to 0 lim (\frac{x ^{3} - 8}{x - 2})

\int e^{x} + 20 (1 + x^{2})^{- 1} d x

\frac{d}{d x} (sin (\frac{x}{4}))

x \to \frac{x}{2} lim (sin (x))

\int - sin (x) \cdot cos (x) d x

What is (\partial)/(\partial y)(1-3/x+y) ?
The answer to (\partial)/(\partial y)(1-3/x+y) is 1