What is (\partial)/(\partial y)(y^2-x) ?

The answer to (\partial)/(\partial y)(y^2-x) is 2y

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(\partial)/(\partial y)(y^2-x)

\frac{\partial}{\partial y} (y^{2} - x)

2 y

Solution steps

\frac{\partial}{\partial y} (y^{2} - x)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (y^{2}) - \frac{\partial}{\partial y} (x)

\frac{\partial}{\partial y} (y^{2}) = 2 y

\frac{\partial}{\partial y} (x) = 0

= 2 y - 0

Simplify

= 2 y

\frac{\partial}{\partial z} (x + y)

\int (\frac{6 x ^{2} - 3 x}{4 x ^{3}}) d x

2 (8^{x})

y^{^{''}} + 21 y = 0

\int x^{2} (\frac{x ^{3}}{12} + 4)^{3} d x

What is (\partial)/(\partial y)(y^2-x) ?
The answer to (\partial)/(\partial y)(y^2-x) is 2y