What is inverse oflaplace 3e^{-3s} ?

The answer to inverse oflaplace 3e^{-3s} is 3\delta(t-3)

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inverse oflaplace 3e^{-3s}

inverse laplace

3 e^{- 3 s}

3 δ (t - 3)

Solution steps

L^{- 1} {3 e^{- 3 s}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 3 L^{- 1} {e^{- 3 s}}

L^{- 1} {e^{- 3 s}} : δ (t - 3)

= 3 δ (t - 3)

x^{2} y^{^{'}} + 2 x y = 19 cos^{2} (x)

y^{^{''}} + 8 y^{^{'}} - 9 y = 0, y (1) = 1, y^{^{'}} (1) = 0

\int r 16 - r^{2} d r

\int_{0}^{2} (3 x^{2} + 2) d x

\int \frac{( x + 2 )}{x ^{2} - 1} d x

What is inverse oflaplace 3e^{-3s} ?
The answer to inverse oflaplace 3e^{-3s} is 3\delta(t-3)