What is the integral of (1-cos(x))^3 ?

The integral of (1-cos(x))^3 is 5/2 x+3/4 sin(2x)-4sin(x)+1/3 sin^3(x)+C

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integral of (1-cos(x))^3

\int (1 - cos (x))^{3} d x

\frac{5}{2} x + \frac{3}{4} sin (2 x) - 4 sin (x) + \frac{1}{3} sin^{3} (x) + C

Solution steps

\int (1 - cos (x))^{3} d x

Expand

(1 - cos (x))^{3} : 1 - 3 cos (x) + 3 cos^{2} (x) - cos^{3} (x)

= \int 1 - 3 cos (x) + 3 cos^{2} (x) - cos^{3} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 1 d x - \int 3 cos (x) d x + \int 3 cos^{2} (x) d x - \int cos^{3} (x) d x

\int 1 d x = x

\int 3 cos (x) d x = 3 sin (x)

\int 3 cos^{2} (x) d x = \frac{3}{2} (x + \frac{1}{2} sin (2 x))

\int cos^{3} (x) d x = sin (x) - \frac{sin ^{3} ( x )}{3}

= x - 3 sin (x) + \frac{3}{2} (x + \frac{1}{2} sin (2 x)) - (sin (x) - \frac{sin ^{3} ( x )}{3})

Simplify

x - 3 sin (x) + \frac{3}{2} (x + \frac{1}{2} sin (2 x)) - (sin (x) - \frac{sin ^{3} ( x )}{3}) : \frac{5}{2} x + \frac{3}{4} sin (2 x) - 4 sin (x) + \frac{1}{3} sin^{3} (x)

= \frac{5}{2} x + \frac{3}{4} sin (2 x) - 4 sin (x) + \frac{1}{3} sin^{3} (x)

Add a constant to the solution

= \frac{5}{2} x + \frac{3}{4} sin (2 x) - 4 sin (x) + \frac{1}{3} sin^{3} (x) + C

x \to - 4 lim (- x^{2} + 2 x - 3)

\int e^{2 x} arctan (e^{x}) d x

arccos (5 x)

\frac{d}{d x} (x^{4} (x - 2)^{3})

y^{^{''}} - 4 y^{^{'}} + 3 y = 7 x^{3} e^{(2 x)} cos (2 x)

What is the integral of (1-cos(x))^3 ?
The integral of (1-cos(x))^3 is 5/2 x+3/4 sin(2x)-4sin(x)+1/3 sin^3(x)+C