What is the integral from 1 to 100 of (37)/(x^3) ?

The integral from 1 to 100 of (37)/(x^3) is 369963/20000

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integral from 1 to 100 of (37)/(x^3)

\int_{1}^{100} \frac{37}{x ^{3}} d x

\frac{369963}{20000}

Decimal Notation

18.49815

Solution steps

\int_{1}^{100} \frac{37}{x ^{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 37 \cdot \int_{1}^{100} \frac{1}{x ^{3}} d x

Apply the Power Rule

: [- \frac{1}{2 x ^{2}}]_{1}^{100}

= 37 [- \frac{1}{2 x ^{2}}]_{1}^{100}

Compute the boundaries:

\frac{9999}{20000}

= 37 \cdot \frac{9999}{20000}

Simplify

= \frac{369963}{20000}

\frac{d}{d x} ((3 + x^{2})^{- 1})

f (x) = 4 x + 3

x - \frac{π}{2}, 1

t \to 0 lim (tan (5 t))

\frac{d}{d x} (\frac{2 x - 3}{3 x + 4})

What is the integral from 1 to 100 of (37)/(x^3) ?
The integral from 1 to 100 of (37)/(x^3) is 369963/20000