What is the derivative of (1/(x^2-9/(x^4))(x+3x^3)) ?

The derivative of (1/(x^2-9/(x^4))(x+3x^3)) is (26)/(x^2)+(27)/(x^4)+3

What is the first derivative of (1/(x^2-9/(x^4))(x+3x^3)) ?

The first derivative of (1/(x^2-9/(x^4))(x+3x^3)) is (26)/(x^2)+(27)/(x^4)+3

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\frac{d}{d x} ((\frac{1}{x ^{2}} - \frac{9}{x ^{4}}) (x + 3 x^{3}))

\frac{26}{x ^{2}} + \frac{27}{x ^{4}} + 3

Solution steps

\frac{d}{d x} ((\frac{1}{x ^{2}} - \frac{9}{x ^{4}}) (x + 3 x^{3}))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = \frac{1}{x ^{2}} - \frac{9}{x ^{4}}, g = x + 3 x^{3}

= \frac{d}{d x} (\frac{1}{x ^{2}} - \frac{9}{x ^{4}}) (x + 3 x^{3}) + \frac{d}{d x} (x + 3 x^{3}) (\frac{1}{x ^{2}} - \frac{9}{x ^{4}})

\frac{d}{d x} (\frac{1}{x ^{2}} - \frac{9}{x ^{4}}) = - \frac{2}{x ^{3}} + \frac{36}{x ^{5}}

\frac{d}{d x} (x + 3 x^{3}) = 1 + 9 x^{2}

= (- \frac{2}{x ^{3}} + \frac{36}{x ^{5}}) (x + 3 x^{3}) + (1 + 9 x^{2}) (\frac{1}{x ^{2}} - \frac{9}{x ^{4}})

Simplify

(- \frac{2}{x ^{3}} + \frac{36}{x ^{5}}) (x + 3 x^{3}) + (1 + 9 x^{2}) (\frac{1}{x ^{2}} - \frac{9}{x ^{4}}) : \frac{26}{x ^{2}} + \frac{27}{x ^{4}} + 3

= \frac{26}{x ^{2}} + \frac{27}{x ^{4}} + 3

\int_{- 2}^{2} 4 - x^{2} d x

\int_{0}^{3} 4 - x d x

\frac{d y}{d x} = \frac{x e ^{2 x}}{x + k}

y^{^{''}} + 2 y^{^{'}} + 14 y = 0, y (0) = 1, y^{^{'}} (0) = 0

\int x^{2} 3 x + 5 d x

What is the derivative of (1/(x^2-9/(x^4))(x+3x^3)) ?
The derivative of (1/(x^2-9/(x^4))(x+3x^3)) is (26)/(x^2)+(27)/(x^4)+3
What is the first derivative of (1/(x^2-9/(x^4))(x+3x^3)) ?
The first derivative of (1/(x^2-9/(x^4))(x+3x^3)) is (26)/(x^2)+(27)/(x^4)+3