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Popular >

integral of 1/(4+x)

Solution

\int \frac{1}{4 + x} d x

Solution

ln ∣ 4 + x ∣ + C

Solution steps

\int \frac{1}{4 + x} d x

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = 4 + x

= ln ∣ 4 + x ∣

Add a constant to the solution

= ln ∣ 4 + x ∣ + C

Popular Examples

(dy)/(dt)=t^2y^3,y(0)=-1

\frac{d y}{d t} = t^{2} y^{3}, y (0) = - 1

derivative of (x+1)/(2x^2+1)derivative of

\frac{x + 1}{2 x ^{2} + 1}

derivative of (tan(x)/(sec(x)))

\frac{d}{d x} (\frac{tan ( x )}{sec ( x )})

(\partial)/(\partial x)(arcsec(x+yz))

\frac{\partial}{\partial x} (arcsec (x + yz))

derivative of f(x)=(x^2)/2+2/(x^2)derivative of

f (x) = \frac{x ^{2}}{2} + \frac{2}{x ^{2}}

Frequently Asked Questions (FAQ)

What is the integral of 1/(4+x) ?
The integral of 1/(4+x) is ln|4+x|+C