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Popular >

y^'=y-x

Solution

y^{^{'}} = y - x

Solution

y = x + 1 + c_{1} e^{x}

Solution steps

y^{'} (x) = y - x

Solve linear ODE:

y = x + 1 + c_{1} e^{x}

y = x + 1 + c_{1} e^{x}

Popular Examples

integral from 0 to 4 of 16-x^3

\int_{0}^{4} 16 - x^{3} d x

(dy)/(dx)-1/x*y-3*x^2=0

\frac{d y}{d x} - \frac{1}{x} \cdot y - 3 \cdot x^{2} = 0

(dy)/(dx)=((e^x))/(ysqrt(1+y^2))

\frac{d y}{d x} = \frac{( e ^{x} )}{y 1 + y ^{2}}

tangent of f(x)=(7x)/(x+4),\at x=3 tangent of

f (x) = \frac{7 x}{x + 4}, at x = 3

integral of sin^3(3x)cos^2(3x)

\int sin^{3} (3 x) cos^{2} (3 x) d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=y-x ?
The solution for y^'=y-x is y=x+1+c_{1}e^x