What is (\partial)/(\partial z)(x^2z^2sin(4y)) ?

The answer to (\partial)/(\partial z)(x^2z^2sin(4y)) is 2x^2zsin(4y)

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(\partial)/(\partial z)(x^2z^2sin(4y))

\frac{\partial}{\partial z} (x^{2} z^{2} sin (4 y))

2 x^{2} z sin (4 y)

Solution steps

\frac{\partial}{\partial z} (x^{2} z^{2} sin (4 y))

Treat

x, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x^{2} sin (4 y) \frac{\partial}{\partial z} (z^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= x^{2} sin (4 y) \cdot 2 z^{2 - 1}

Simplify

= 2 x^{2} z sin (4 y)

\frac{\partial}{\partial x} (sin (\frac{2 x}{y}))

- 5 w^{- 7} + 3 w

x \to 1 lim (\frac{x}{x - 1})

f (x) = (7 x^{2} + 6) (5 x + 8 + \frac{7}{x})

sin^{2} (y)

What is (\partial)/(\partial z)(x^2z^2sin(4y)) ?
The answer to (\partial)/(\partial z)(x^2z^2sin(4y)) is 2x^2zsin(4y)