What is the derivative of f(t)=(t^2-4)/(t-2) ?

The derivative of f(t)=(t^2-4)/(t-2) is 1

What is the first derivative of f(t)=(t^2-4)/(t-2) ?

The first derivative of f(t)=(t^2-4)/(t-2) is 1

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derivative of

f (t) = \frac{t ^{2} - 4}{t - 2}

1

Solution steps

\frac{d}{d t} (\frac{t ^{2} - 4}{t - 2})

Simplify

\frac{t ^{2} - 4}{t - 2} : t + 2

= \frac{d}{d t} (t + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d t}{d t} + \frac{d}{d t} (2)

\frac{d t}{d t} = 1

\frac{d}{d t} (2) = 0

= 1 + 0

Simplify

= 1

\frac{6}{x ^{2}}

\int 3 x (3 x^{2} + 7) d x

f (x) = 3 x^{4} + 2 e^{x}, at x = 0

\frac{( s + 3 )}{s ^{2} + s + 3}

\frac{d}{d x} \frac{d y}{d x} - a^{2} y + b = 0

What is the derivative of f(t)=(t^2-4)/(t-2) ?
The derivative of f(t)=(t^2-4)/(t-2) is 1
What is the first derivative of f(t)=(t^2-4)/(t-2) ?
The first derivative of f(t)=(t^2-4)/(t-2) is 1