en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=x+1,y=0,x=0,x=2

Solution

area

y = x + 1, y = 0, x = 0, x = 2

Solution

4

Solution steps

Apply the area formula:

\int_{0}^{2} ∣ x + 1 ∣ d x

Solve

\int_{0}^{2} ∣ x + 1 ∣ d x : 4

The area is:

= 4

Popular Examples

inverse oflaplace 6/((s+1)^6)inverse laplace

\frac{6}{( s + 1 ) ^{6}}

derivative of (4x+7)^3 derivative of

(4 x + 7)^{3}

integral of xsqrt(x^2+16)

\int x x^{2} + 16 d x

integral of-xcos(x^2)

\int - x cos (x^{2}) d x

d/(dθ)(cos(2θ))

\frac{d}{d θ} (cos (2 θ))

Frequently Asked Questions (FAQ)

What is area y=x+1,y=0,x=0,x=2 ?
The answer to area y=x+1,y=0,x=0,x=2 is 4