What is the derivative of x-e^{-x} ?

The derivative of x-e^{-x} is 1+e^{-x}

What is the first derivative of x-e^{-x} ?

The first derivative of x-e^{-x} is 1+e^{-x}

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\frac{d}{d x} (x - e^{- x})

1 + e^{- x}

Solution steps

\frac{d}{d x} (x - e^{- x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} - \frac{d}{d x} (e^{- x})

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{- x}) = - e^{- x}

= 1 - (- e^{- x})

Simplify

= 1 + e^{- x}

\int (3 x + 2)^{2.4} d x

\frac{\partial}{\partial x} (x^{6} y - 2 x^{5} y^{2})

- 2 x^{4} + 5 x^{2} - 3 (1)

y = e^{t}

x^{2} \frac{d y}{d x} = y

What is the derivative of x-e^{-x} ?
The derivative of x-e^{-x} is 1+e^{-x}
What is the first derivative of x-e^{-x} ?
The first derivative of x-e^{-x} is 1+e^{-x}