What is the solution for (dy)/(dx)=e^{8x-3y},y(0)=4 ?

The solution for (dy)/(dx)=e^{8x-3y},y(0)=4 is y=(ln(3/8 e^{8x}+e^{12}-3/8))/3

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(dy)/(dx)=e^{8x-3y},y(0)=4

\frac{d y}{d x} = e^{8 x - 3 y}, y (0) = 4

y = \frac{ln ( \frac{3}{8} e ^{8 x} + e ^{12} - \frac{3}{8} )}{3}

Solution steps

\frac{d y}{d x} = e^{8 x - 3 y}

Solve separable ODE:

y = \frac{ln ( \frac{3}{8} e ^{8 x} + e ^{12} - \frac{3}{8} )}{3}

y = \frac{ln ( \frac{3}{8} e ^{8 x} + e ^{12} - \frac{3}{8} )}{3}

f (x) = \frac{x ^{2}}{( 4 + x )}

- 9 x^{\frac{1}{3}} + 5, at x = 27

\frac{d}{d x} (x^{2} - 2 x - \frac{2}{x ^{4}})

\int + (x^{2} - 1) d x

\int π^{2} d x

What is the solution for (dy)/(dx)=e^{8x-3y},y(0)=4 ?
The solution for (dy)/(dx)=e^{8x-3y},y(0)=4 is y=(ln(3/8 e^{8x}+e^{12}-3/8))/3