What is the derivative of-x^3+4 ?

The derivative of-x^3+4 is -3x^2

What is the first derivative of-x^3+4 ?

The first derivative of-x^3+4 is -3x^2

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\frac{d}{d x} (- x^{3} + 4)

- 3 x^{2}

Solution steps

\frac{d}{d x} (- x^{3} + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{3}) + \frac{d}{d x} (4)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (4) = 0

= - 3 x^{2} + 0

Simplify

= - 3 x^{2}

\frac{\partial}{\partial x} (\frac{y}{2 x} - 1)

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