What is the derivative of 2ln(3x) ?

The derivative of 2ln(3x) is 2/x

What is the first derivative of 2ln(3x) ?

The first derivative of 2ln(3x) is 2/x

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derivative of

2 ln (3 x)

\frac{2}{x}

Solution steps

\frac{d}{d x} (2 ln (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (ln (3 x))

Apply the chain rule:

\frac{1}{3 x} \frac{d}{d x} (3 x)

= \frac{1}{3 x} \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= 2 \cdot \frac{1}{3 x} \cdot 3

Simplify

2 \cdot \frac{1}{3 x} \cdot 3 : \frac{2}{x}

= \frac{2}{x}

\int \frac{x}{( x ^{2} + y ^{2} )} d x

x^{3} - 2 x + 1

x \cdot \frac{d y}{d x} + y = e^{x}

\frac{d y}{d x} + \frac{y}{x} = \frac{1}{x y ^{2}}

- 4 cos (2 t)

What is the derivative of 2ln(3x) ?
The derivative of 2ln(3x) is 2/x
What is the first derivative of 2ln(3x) ?
The first derivative of 2ln(3x) is 2/x