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Popular >

y^'-y/x =y^2

Solution

y^{^{'}} - \frac{y}{x} = y^{2}

Solution

y = \frac{2 x}{- x ^{2} + c _{1}}

Solution steps

y^{'} (x) - \frac{y}{x} = y^{2}

Solve Bernoulli ODE:

y = \frac{2 x}{- x ^{2} + c _{1}}

y = \frac{2 x}{- x ^{2} + c _{1}}

Popular Examples

sqrt(xy)((dy)/(dx))=3

x y (\frac{d y}{d x}) = 3

integral from 1 to 4 of (5ln(x))/(x^2)

\int_{1}^{4} \frac{5 ln ( x )}{x ^{2}} d x

derivative of 1-e^{-x}-xe^{-x}

\frac{d}{d x} (1 - e^{- x} - x e^{- x})

ty^'=y-5t^2sin(3t),y(pi/3)=0

t y^{^{'}} = y - 5 t^{2} sin (3 t), y (\frac{π}{3}) = 0

(\partial)/(\partial x)(e^{2x}sin(y))

\frac{\partial}{\partial x} (e^{2 x} sin (y))

Frequently Asked Questions (FAQ)

What is the solution for y^'-y/x =y^2 ?
The solution for y^'-y/x =y^2 is y=(2x)/(-x^2+c_{1)}