What is the solution for y^'=-ky^{1/2} ?

The solution for y^'=-ky^{1/2} is y=(k^2t^2)/4-(c_{1}kt)/2+(c_{1}^2)/4

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y^'=-ky^{1/2}

y^{^{'}} = - k y^{\frac{1}{2}}

y = \frac{k ^{2} t ^{2}}{4} - \frac{c _{1} k t}{2} + \frac{c _{1}^{2}}{4}

Solution steps

y^{'} (t) = - k y (t)^{\frac{1}{2}}

Solve separable ODE:

y = \frac{k ^{2} t ^{2}}{4} - \frac{c _{1} k t}{2} + \frac{c _{1}^{2}}{4}

y = \frac{k ^{2} t ^{2}}{4} - \frac{c _{1} k t}{2} + \frac{c _{1}^{2}}{4}

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What is the solution for y^'=-ky^{1/2} ?
The solution for y^'=-ky^{1/2} is y=(k^2t^2)/4-(c_{1}kt)/2+(c_{1}^2)/4