What is the derivative of-3x^4+2y^2 ?

The derivative of-3x^4+2y^2 is -12x^3+4y(dy)/(dx)

What is the first derivative of-3x^4+2y^2 ?

The first derivative of-3x^4+2y^2 is -12x^3+4y(dy)/(dx)

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\frac{d}{d x} (- 3 x^{4} + 2 y^{2})

- 12 x^{3} + 4 y \frac{d y}{d x}

Solution steps

\frac{d}{d x} (- 3 x^{4} + 2 y^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (3 x^{4}) + \frac{d}{d x} (2 y^{2})

\frac{d}{d x} (3 x^{4}) = 12 x^{3}

\frac{d}{d x} (2 y^{2}) = 4 y \frac{d y}{d x}

= - 12 x^{3} + 4 y \frac{d y}{d x}

\frac{2 x + 1}{4 x ^{2} + 1}

\int x cos (a x) d x

\frac{\partial}{\partial x} (z e^{x yz})

\frac{1}{1 - x}

x \cdot \frac{d y}{d x} = y^{2} - y

What is the derivative of-3x^4+2y^2 ?
The derivative of-3x^4+2y^2 is -12x^3+4y(dy)/(dx)
What is the first derivative of-3x^4+2y^2 ?
The first derivative of-3x^4+2y^2 is -12x^3+4y(dy)/(dx)