What is the derivative of (sqrt(x)/(x+4)) ?

The derivative of (sqrt(x)/(x+4)) is (-x+4)/(2sqrt(x)(x+4)^2)

What is the first derivative of (sqrt(x)/(x+4)) ?

The first derivative of (sqrt(x)/(x+4)) is (-x+4)/(2sqrt(x)(x+4)^2)

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\frac{d}{d x} (\frac{x}{x + 4})

\frac{- x + 4}{2 x ( x + 4 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x}{x + 4})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ) ( x + 4 ) - \frac{d}{d x} ( x + 4 ) x}{( x + 4 ) ^{2}}

\frac{d}{d x} (x) = \frac{1}{2 x}

\frac{d}{d x} (x + 4) = 1

= \frac{\frac{1}{2 x} ( x + 4 ) - 1 \cdot x}{( x + 4 ) ^{2}}

Simplify

\frac{\frac{1}{2 x} ( x + 4 ) - 1 \cdot x}{( x + 4 ) ^{2}} : \frac{- x + 4}{2 x ( x + 4 ) ^{2}}

= \frac{- x + 4}{2 x ( x + 4 ) ^{2}}

\int \frac{1 + e ^{2 x}}{e ^{x - 1}} d x

\int 1 - \frac{3}{14 - x} d x

\int \frac{3}{x + 3 + x} d x

\frac{d y}{d t} + y = 7 t

(7, - 2), (3, 5)

What is the derivative of (sqrt(x)/(x+4)) ?
The derivative of (sqrt(x)/(x+4)) is (-x+4)/(2sqrt(x)(x+4)^2)
What is the first derivative of (sqrt(x)/(x+4)) ?
The first derivative of (sqrt(x)/(x+4)) is (-x+4)/(2sqrt(x)(x+4)^2)