What is the tangent of 1/(sqrt(11x)),\at x=9 ?

The tangent of 1/(sqrt(11x)),\at x=9 is y=-1/(54sqrt(11))x+1/(2sqrt(11))

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tangent of 1/(sqrt(11x)),\at x=9

tangent of

\frac{1}{11 x}, at x = 9

y = - \frac{1}{54 11} x + \frac{1}{2 11}

Solution steps

Find the tangent point:

(9, \frac{1}{3 11})

Find the slope of

y = \frac{1}{11 x} : \frac{d y}{d x} = - \frac{1}{2 11 x ^{\frac{3}{2}}}

Compute the slope of

y = \frac{1}{11 x}

x = 9 : m = - \frac{1}{54 11}

Find the line with slope m=

- \frac{1}{54 11}

and passing through

(9, \frac{1}{3 11}) : y = - \frac{1}{54 11} x + \frac{1}{2 11}

y = - \frac{1}{54 11} x + \frac{1}{2 11}

x \to 0 lim (\frac{1}{1 + cos ( x )})

\int cos^{5} (2 x) d x

\frac{d}{d x} (x^{1 - n})

\frac{d}{d x} (\frac{3}{4} (x^{2} - 1)^{\frac{2}{3}})

\int 7 sin^{3} (x) cos^{2} (x) d x

What is the tangent of 1/(sqrt(11x)),\at x=9 ?
The tangent of 1/(sqrt(11x)),\at x=9 is y=-1/(54sqrt(11))x+1/(2sqrt(11))