What is the integral from 0 to 1 of 1-x^{2/7} ?

The integral from 0 to 1 of 1-x^{2/7} is 2/9

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integral from 0 to 1 of 1-x^{2/7}

\int_{0}^{1} 1 - x^{\frac{2}{7}} d x

\frac{2}{9}

Decimal Notation

0.22222 \dots

Solution steps

\int_{0}^{1} 1 - x^{\frac{2}{7}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 1 d x - \int_{0}^{1} x^{\frac{2}{7}} d x

\int_{0}^{1} 1 d x = 1

\int_{0}^{1} x^{\frac{2}{7}} d x = \frac{7}{9}

= 1 - \frac{7}{9}

Simplify

1 - \frac{7}{9} : \frac{2}{9}

= \frac{2}{9}

x^{2} - 3 x y + x y^{^{'}} = 0

\frac{d}{d t} (cos (t))

\frac{d}{d x} (ln (\frac{5 x + 1}{5 x - 1}))

\frac{d}{d x} (15 x^{2} + 3)

y^{^{''}} + 4 y^{^{'}} + 5 y = 0, y (0) = 1, y^{^{'}} (0) = 0

What is the integral from 0 to 1 of 1-x^{2/7} ?
The integral from 0 to 1 of 1-x^{2/7} is 2/9