What is the derivative of sqrt(33+4t) ?

The derivative of sqrt(33+4t) is 2/(sqrt(33+4t))

What is the first derivative of sqrt(33+4t) ?

The first derivative of sqrt(33+4t) is 2/(sqrt(33+4t))

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derivative of

33 + 4 t

\frac{2}{33 + 4 t}

Solution steps

\frac{d}{d t} (33 + 4 t)

Apply the chain rule:

\frac{1}{2 33 + 4 t} \frac{d}{d t} (33 + 4 t)

= \frac{1}{2 33 + 4 t} \frac{d}{d t} (33 + 4 t)

\frac{d}{d t} (33 + 4 t) = 4

= \frac{1}{2 33 + 4 t} \cdot 4

Simplify

\frac{1}{2 33 + 4 t} \cdot 4 : \frac{2}{33 + 4 t}

= \frac{2}{33 + 4 t}

\frac{x ^{2}}{( 4 + x )}

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What is the derivative of sqrt(33+4t) ?
The derivative of sqrt(33+4t) is 2/(sqrt(33+4t))
What is the first derivative of sqrt(33+4t) ?
The first derivative of sqrt(33+4t) is 2/(sqrt(33+4t))