What is (\partial)/(\partial y)(x^2y^4) ?

The answer to (\partial)/(\partial y)(x^2y^4) is 4x^2y^3

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(\partial)/(\partial y)(x^2y^4)

\frac{\partial}{\partial y} (x^{2} y^{4})

4 x^{2} y^{3}

Solution steps

\frac{\partial}{\partial y} (x^{2} y^{4})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x^{2} \frac{\partial}{\partial y} (y^{4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= x^{2} \cdot 4 y^{4 - 1}

Simplify

= 4 x^{2} y^{3}

x \to 2 lim (\frac{x ^{2} - 2}{x - 2})

n = 0 \sum \infty 2 + 0.8 6^{n}

\int csc^{3} (2 x) d x

x \to 0 lim (sin (5 x) csc (9 x))

\frac{( s + 1 ) ^{3}}{s ^{4}}

What is (\partial)/(\partial y)(x^2y^4) ?
The answer to (\partial)/(\partial y)(x^2y^4) is 4x^2y^3