What is (\partial)/(\partial x)(cos(3x+4y)) ?

The answer to (\partial)/(\partial x)(cos(3x+4y)) is -sin(3x+4y)*3

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(\partial)/(\partial x)(cos(3x+4y))

\frac{\partial}{\partial x} (cos (3 x + 4 y))

- sin (3 x + 4 y) \cdot 3

Solution steps

\frac{\partial}{\partial x} (cos (3 x + 4 y))

Treat

y

as a constant

Apply the chain rule:

- sin (3 x + 4 y) \frac{\partial}{\partial x} (3 x + 4 y)

= - sin (3 x + 4 y) \frac{\partial}{\partial x} (3 x + 4 y)

\frac{\partial}{\partial x} (3 x + 4 y) = 3

= - sin (3 x + 4 y) \cdot 3

x \to 1 lim (3 - 2 x)

\int sin (x) \cdot sin (2 x) d x

y = x, y = - x + 3, y = 0

\int (sin^{2} (2 x)) d x

\frac{d y}{d x} = \frac{y ^{3}}{3 x - 2}

What is (\partial)/(\partial x)(cos(3x+4y)) ?
The answer to (\partial)/(\partial x)(cos(3x+4y)) is -sin(3x+4y)*3