What is the integral from 2 to 5 of x^4ln(2x) ?

The integral from 2 to 5 of x^4ln(2x) is 625ln(10)-3093/25-64/5 ln(2)

Popular >

integral from 2 to 5 of x^4ln(2x)

\int_{2}^{5} x^{4} ln (2 x) d x

625 ln (10) - \frac{3093}{25} - \frac{64}{5} ln (2)

Decimal Notation

1306.52339 \dots

Solution steps

\int_{2}^{5} x^{4} ln (2 x) d x

Apply Integration By Parts

: [\frac{1}{5} x^{5} ln (2 x) - \int \frac{x ^{4}}{5} d x]_{2}^{5}

= [\frac{1}{5} x^{5} ln (2 x) - \int \frac{x ^{4}}{5} d x]_{2}^{5}

\int \frac{x ^{4}}{5} d x = \frac{x ^{5}}{25}

= [\frac{1}{5} x^{5} ln (2 x) - \frac{x ^{5}}{25}]_{2}^{5}

Compute the boundaries:

625 ln (10) - \frac{3093}{25} - \frac{64}{5} ln (2)

= 625 ln (10) - \frac{3093}{25} - \frac{64}{5} ln (2)

\int_{0}^{18} t^{2} + 2 t + 1 d t

\frac{\partial}{\partial y} (3 y - e^{s i n (x)})

x \to 3 - lim (\frac{6 x}{2 x - 5})

\int_{4}^{\infty} \frac{ln ( x )}{x} d x

\frac{d}{d θ} (\frac{1}{4} sin^{2} (2 θ))

What is the integral from 2 to 5 of x^4ln(2x) ?
The integral from 2 to 5 of x^4ln(2x) is 625ln(10)-3093/25-64/5 ln(2)