What is the derivative of e^{x^3-x} ?

The derivative of e^{x^3-x} is e^{x^3-x}(3x^2-1)

What is the first derivative of e^{x^3-x} ?

The first derivative of e^{x^3-x} is e^{x^3-x}(3x^2-1)

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\frac{d}{d x} (e^{x^{3} - x})

e^{x^{3} - x} (3 x^{2} - 1)

Solution steps

\frac{d}{d x} (e^{x^{3} - x})

Apply the chain rule:

e^{x^{3} - x} \frac{d}{d x} (x^{3} - x)

= e^{x^{3} - x} \frac{d}{d x} (x^{3} - x)

\frac{d}{d x} (x^{3} - x) = 3 x^{2} - 1

= e^{x^{3} - x} (3 x^{2} - 1)

n = 0 \sum \infty e^{- \frac{3 n}{2}}

\frac{d}{d x _{0}} (x_{0})

x \to 2 lim (e^{\frac{3}{2 - x}})

\int 4 x^{2} + 2 + \frac{5}{x ^{2} + 1} d x

\int x e^{- 18 x} d x

What is the derivative of e^{x^3-x} ?
The derivative of e^{x^3-x} is e^{x^3-x}(3x^2-1)
What is the first derivative of e^{x^3-x} ?
The first derivative of e^{x^3-x} is e^{x^3-x}(3x^2-1)