What is (\partial)/(\partial y)(2xy+3y) ?

The answer to (\partial)/(\partial y)(2xy+3y) is 2x+3

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(\partial)/(\partial y)(2xy+3y)

\frac{\partial}{\partial y} (2 x y + 3 y)

2 x + 3

Solution steps

\frac{\partial}{\partial y} (2 x y + 3 y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 x y) + \frac{\partial}{\partial y} (3 y)

\frac{\partial}{\partial y} (2 x y) = 2 x

\frac{\partial}{\partial y} (3 y) = 3

= 2 x + 3

\int 2 x + 1 d x

\int x^{2} x^{3 + 1} d x

x \to - 1 lim (\frac{x - 1}{x ^{1} - 1})

\int \frac{x ^{3} + x - 2}{x ^{4} + 2 x ^{3} + 3 x ^{2}} d x

(x^{2} + y^{2})^{2} = 4 x^{2} y, (- 1, 1)

What is (\partial)/(\partial y)(2xy+3y) ?
The answer to (\partial)/(\partial y)(2xy+3y) is 2x+3