What is the tangent of f(x)= 1/(x^3),\at x=1 ?

The tangent of f(x)= 1/(x^3),\at x=1 is y=-3x+4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)= 1/(x^3),\at x=1

tangent of

f (x) = \frac{1}{x ^{3}}, at x = 1

y = - 3 x + 4

Solution steps

Find the tangent point:

(1, 1)

Find the slope of

f (x) = \frac{1}{x ^{3}} : \frac{df ( x )}{d x} = - \frac{3}{x ^{4}}

Compute the slope of

f (x) = \frac{1}{x ^{3}}

x = 1 : m = - 3

Find the line with slope m=

- 3

and passing through

(1, 1) : y = - 3 x + 4

y = - 3 x + 4

\frac{\partial}{\partial x} (y^{6} sin (5 x))

arctan (\frac{4}{x})

\frac{d y}{d x} + y = \frac{e ^{x}}{y}

\int_{3}^{4} e^{3 - x} d x

\int \frac{1}{6 x ^{6}} d x

What is the tangent of f(x)= 1/(x^3),\at x=1 ?
The tangent of f(x)= 1/(x^3),\at x=1 is y=-3x+4