What is (\partial}{\partial x}(-\frac{9x)/y) ?

The answer to (\partial}{\partial x}(-\frac{9x)/y) is -9/y

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(\partial}{\partial x}(-\frac{9x)/y)

\frac{\partial}{\partial x} (- \frac{9 x}{y})

- \frac{9}{y}

Solution steps

\frac{\partial}{\partial x} (- \frac{9 x}{y})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{9}{y} \frac{\partial}{\partial x} (x)

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= - \frac{9}{y} \cdot 1

Simplify

= - \frac{9}{y}

- x^{^{'}} - \frac{x}{0.00022} + 13364 = 0

\frac{d}{d x} (ln (\frac{x + 2}{x + 1}))

\int \frac{a + b x ^{8}}{9 a x + b x ^{9}} d x

x \to \infty lim (b^{x})

cos (t - \frac{π}{6})

What is (\partial}{\partial x}(-\frac{9x)/y) ?
The answer to (\partial}{\partial x}(-\frac{9x)/y) is -9/y