What is the solution for (5du)/(dt)=u^2 ?

The solution for (5du)/(dt)=u^2 is t=-5/u+c_{1}

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(5du)/(dt)=u^2

\frac{5 d u}{d t} = u^{2}

t = - \frac{5}{u} + c_{1}

Solution steps

\frac{5 d u}{d t} = u^{2}

Let

t

be the dependent variable. Divide by

d u

\frac{5}{\frac{d t}{d u}} = u^{2}

Substitute

\frac{d t}{d u}

with

t^{'} (u)

\frac{5}{t ^{^{'}} ( u )} = u^{2}

Isolate

t^{'} (u) : t^{'} (u) = \frac{5}{u ^{2}}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

t = \int \frac{5}{u ^{2}} d u

\int \frac{5}{u ^{2}} d u = - \frac{5}{u} + c_{1}

t = - \frac{5}{u} + c_{1}

cos (\frac{1}{x})

t \to 2 + lim (\frac{t + 2}{t ^{2} - 4})

6 sin (x)

\frac{1}{( 4 - x ^{2} )}

\int \frac{1}{y ln ^{2} ( y )} d y

What is the solution for (5du)/(dt)=u^2 ?
The solution for (5du)/(dt)=u^2 is t=-5/u+c_{1}