What is the derivative of ax^2+b-4 ?

The derivative of ax^2+b-4 is 2ax

What is the first derivative of ax^2+b-4 ?

The first derivative of ax^2+b-4 is 2ax

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\frac{d}{d x} (a x^{2} + b - 4)

2 a x

Solution steps

\frac{d}{d x} (a x^{2} + b - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (a x^{2}) + \frac{d b}{d x} - \frac{d}{d x} (4)

\frac{d}{d x} (a x^{2}) = 2 a x

\frac{d b}{d x} = 0

\frac{d}{d x} (4) = 0

= 2 a x + 0 - 0

Simplify

= 2 a x

\frac{2 s + 1}{s ^{3} + 7 s ^{2} + 12 s}

\frac{d}{d x} (cosh (0))

e^{x}, x^{2} - 1, x = - 1, x = 1

\int 29 sec^{- 2} (x t a) n^{3} x

x \to 0 lim (x^{2} + y^{2})

What is the derivative of ax^2+b-4 ?
The derivative of ax^2+b-4 is 2ax
What is the first derivative of ax^2+b-4 ?
The first derivative of ax^2+b-4 is 2ax