What is the d/(dt)(e^{rt}) ?

The d/(dt)(e^{rt}) is e^{rt}(t(dr)/(dt)+r)

What is the first d/(dt)(e^{rt}) ?

The first d/(dt)(e^{rt}) is e^{rt}(t(dr)/(dt)+r)

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\frac{d}{d t} (e^{r t})

e^{r t} (t \frac{d r}{d t} + r)

Solution steps

\frac{d}{d t} (e^{r t})

Apply the chain rule:

e^{r t} \frac{d}{d t} (r t)

= e^{r t} \frac{d}{d t} (r t)

\frac{d}{d t} (r t) = t \frac{d r}{d t} + r

= e^{r t} (t \frac{d r}{d t} + r)

\int e^{- 4 l n (x)} d x

(7 + x^{12}) \frac{d y}{d x} = x^{11} y

x \to - 4 lim (\frac{x}{x + 4})

x \to 3 - lim (- x^{2} + \frac{5}{2} x + 3)

\frac{d}{d x} (5 x^{4} sin^{3} (2 x))

What is the d/(dt)(e^{rt}) ?
The d/(dt)(e^{rt}) is e^{rt}(t(dr)/(dt)+r)
What is the first d/(dt)(e^{rt}) ?
The first d/(dt)(e^{rt}) is e^{rt}(t(dr)/(dt)+r)