What is the integral from 7 to e^4 of 1/x ?

The integral from 7 to e^4 of 1/x is 4-ln(7)

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integral from 7 to e^4 of 1/x

\int_{7}^{e^{4}} \frac{1}{x} d x

4 - ln (7)

Decimal Notation

2.05408 \dots

Solution steps

\int_{7}^{e^{4}} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{7}^{e^{4}}

Compute the boundaries:

4 - ln (7)

= 4 - ln (7)

7 x - x^{2}, 2 x, 0, 5

\frac{2 t}{t ^{2} + 1}

\int ∣ x + 2 ∣ d x

\frac{d}{d x} ((5 x^{2} - 3) \cdot (x^{2} + x + 4))

\frac{d}{d x} (e^{x} (12 x^{2} - 24 x + 24))

What is the integral from 7 to e^4 of 1/x ?
The integral from 7 to e^4 of 1/x is 4-ln(7)