What is the derivative of 1/(3x-2) ?

The derivative of 1/(3x-2) is -3/((3x-2)^2)

What is the first derivative of 1/(3x-2) ?

The first derivative of 1/(3x-2) is -3/((3x-2)^2)

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derivative of

\frac{1}{3 x - 2}

- \frac{3}{( 3 x - 2 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{3 x - 2})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((3 x - 2)^{- 1})

Apply the chain rule:

- \frac{1}{( 3 x - 2 ) ^{2}} \frac{d}{d x} (3 x - 2)

= - \frac{1}{( 3 x - 2 ) ^{2}} \frac{d}{d x} (3 x - 2)

\frac{d}{d x} (3 x - 2) = 3

= - \frac{1}{( 3 x - 2 ) ^{2}} \cdot 3

Simplify

- \frac{1}{( 3 x - 2 ) ^{2}} \cdot 3 : - \frac{3}{( 3 x - 2 ) ^{2}}

= - \frac{3}{( 3 x - 2 ) ^{2}}

n = 0 \sum \infty (\frac{- 1}{5})^{n}

\frac{\partial}{\partial x} (5 e^{6 x})

\int_{0}^{7} (7 - x)^{2} d x

y^{^{''}} - 3 y^{^{'}} + 2 y = 0, y (0) = 1, y^{^{'}} (0) = \frac{2}{3}

\frac{d}{d x} (\frac{ln ( x )}{x ^{2}})

What is the derivative of 1/(3x-2) ?
The derivative of 1/(3x-2) is -3/((3x-2)^2)
What is the first derivative of 1/(3x-2) ?
The first derivative of 1/(3x-2) is -3/((3x-2)^2)