What is (\partial)/(\partial t)(2rsin(t)) ?

The answer to (\partial)/(\partial t)(2rsin(t)) is 2rcos(t)

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(\partial)/(\partial t)(2rsin(t))

\frac{\partial}{\partial t} (2 r sin (t))

2 r cos (t)

Solution steps

\frac{\partial}{\partial t} (2 r sin (t))

Treat

r

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 r \frac{\partial}{\partial t} (sin (t))

Apply the common derivative:

\frac{\partial}{\partial t} (sin (t)) = cos (t)

= 2 r cos (t)

\frac{d}{d x} (x^{3} - 9 x^{2} + 10 x)

\int 1 + cos (y) d y

\int \frac{3 x ^{2} + 4 x - 6}{x ^{2} + 16 x + 64} d x

\frac{d}{d x} (x^{x})

\int \frac{x + 2}{x - 4} d x

What is (\partial)/(\partial t)(2rsin(t)) ?
The answer to (\partial)/(\partial t)(2rsin(t)) is 2rcos(t)