What is the limit as x approaches-1 of \sqrt[3]{x}+1 ?

The limit as x approaches-1 of \sqrt[3]{x}+1 is \sqrt[3]{-1}+1

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limit as x approaches-1 of \sqrt[3]{x}+1

Solution steps

Plug in the value

x = - 1

\frac{d}{d x} (x y^{2} - x^{2} y + x^{2} + y^{2})

x \to - 6 lim (\frac{x + 1 + 5}{x + 6})

x \to 9 lim (\frac{2 x - 1}{x + 3})

\frac{\partial}{\partial z} (x \cdot cos (y) \cdot sin (z))

\frac{d}{d t} (\frac{1}{t ^{2} + 1})

What is the limit as x approaches-1 of \sqrt[3]{x}+1 ?
The limit as x approaches-1 of \sqrt[3]{x}+1 is \sqrt[3]{-1}+1