What is the integral from 0 to 3 of x^2e^{-x} ?

The integral from 0 to 3 of x^2e^{-x} is -(17)/(e^3)+2

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integral from 0 to 3 of x^2e^{-x}

\int_{0}^{3} x^{2} e^{- x} d x

- \frac{17}{e ^{3}} + 2

Decimal Notation

1.15361 \dots

Solution steps

\int_{0}^{3} x^{2} e^{- x} d x

Apply Integration By Parts

: [- e^{- x} x^{2} - \int - 2 e^{- x} x d x]_{0}^{3}

= [- e^{- x} x^{2} - \int - 2 e^{- x} x d x]_{0}^{3}

\int - 2 e^{- x} x d x = - 2 (- e^{- x} x - e^{- x})

= [- e^{- x} x^{2} - (- 2 (- e^{- x} x - e^{- x}))]_{0}^{3}

Simplify

= [- e^{- x} x^{2} + 2 (- e^{- x} x - e^{- x})]_{0}^{3}

Compute the boundaries:

- \frac{17}{e ^{3}} + 2

= - \frac{17}{e ^{3}} + 2

x^{\frac{5}{2}}

\int (lo g_{e} (x))^{2} d x

\int \frac{x ^{2} + 4}{x} d x

\int (\frac{4}{x ^{2}} + 2 - \frac{1}{8 x ^{3}}) d x

What is the integral from 0 to 3 of x^2e^{-x} ?
The integral from 0 to 3 of x^2e^{-x} is -(17)/(e^3)+2