What is the derivative of-4x^3+4x ?

The derivative of-4x^3+4x is -12x^2+4

What is the first derivative of-4x^3+4x ?

The first derivative of-4x^3+4x is -12x^2+4

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\frac{d}{d x} (- 4 x^{3} + 4 x)

- 12 x^{2} + 4

Solution steps

\frac{d}{d x} (- 4 x^{3} + 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (4 x^{3}) + \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (4 x) = 4

= - 12 x^{2} + 4

x^{2}, (0, 3)

\int c (x) d x

h (x) = [\frac{x + 1}{x - 1}]^{3}

\frac{\partial}{\partial x} ((\frac{y}{z})^{\frac{1}{x}})

y^{^{''}} + 3 y = 48 x^{2} e^{3 x}

What is the derivative of-4x^3+4x ?
The derivative of-4x^3+4x is -12x^2+4
What is the first derivative of-4x^3+4x ?
The first derivative of-4x^3+4x is -12x^2+4