What is (\partial)/(\partial x)(sin(7x+y+3z)) ?

The answer to (\partial)/(\partial x)(sin(7x+y+3z)) is cos(7x+y+3z)*7

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(\partial)/(\partial x)(sin(7x+y+3z))

\frac{\partial}{\partial x} (sin (7 x + y + 3 z))

cos (7 x + y + 3 z) \cdot 7

Solution steps

\frac{\partial}{\partial x} (sin (7 x + y + 3 z))

Treat

y, z

as constants

Apply the chain rule:

cos (7 x + y + 3 z) \frac{\partial}{\partial x} (7 x + y + 3 z)

= cos (7 x + y + 3 z) \frac{\partial}{\partial x} (7 x + y + 3 z)

\frac{\partial}{\partial x} (7 x + y + 3 z) = 7

= cos (7 x + y + 3 z) \cdot 7

\frac{d}{d x} (6 + 7 x)

e^{3 x}, 0

\frac{2 s - 3}{s ^{2} + 2}

\int \frac{7 x}{x ^{2} + 1} d x

f (x) = sec (θ) tan (θ)

What is (\partial)/(\partial x)(sin(7x+y+3z)) ?
The answer to (\partial)/(\partial x)(sin(7x+y+3z)) is cos(7x+y+3z)*7