What is (\partial)/(\partial h)(1/2 (a+b)h) ?

The answer to (\partial)/(\partial h)(1/2 (a+b)h) is 1/2 (a+b)

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(\partial)/(\partial h)(1/2 (a+b)h)

\frac{\partial}{\partial h} (\frac{1}{2} (a + b) h)

\frac{1}{2} (a + b)

Solution steps

\frac{\partial}{\partial h} (\frac{1}{2} (a + b) h)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} (a + b) \frac{\partial}{\partial h} (h)

Apply the common derivative:

\frac{\partial}{\partial h} (h) = 1

= \frac{1}{2} (a + b) \cdot 1

Simplify

= \frac{1}{2} (a + b)

\frac{d}{d x} (\frac{2}{x ^{\frac{1}{3}}} - 2)

f (x) = - 5 x (2 x - 3)^{4}

y^{^{''}} - 2 y^{^{'}} + 5 y = 5, y (0) = 2, y^{^{'}} (0) = 1

\int \frac{( 1 - tan ^{2} ( x ) )}{sec ^{2} ( x )} d x

f (x) = (\frac{x - 3}{x + 1})^{2}, at x = 0

What is (\partial)/(\partial h)(1/2 (a+b)h) ?
The answer to (\partial)/(\partial h)(1/2 (a+b)h) is 1/2 (a+b)