What is the integral of (sin(x))/3 ?

The integral of (sin(x))/3 is -1/3 cos(x)+C

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integral of (sin(x))/3

\int \frac{sin ( x )}{3} d x

- \frac{1}{3} cos (x) + C

Solution steps

\int \frac{sin ( x )}{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= \frac{1}{3} (- cos (x))

Simplify

= - \frac{1}{3} cos (x)

Add a constant to the solution

= - \frac{1}{3} cos (x) + C

\int_{1}^{2} (x^{2} - 4) d x

\int 2 cos^{2} (t) sin^{2} (t) d t

f (x) = x^{2} + 3 x + 5, (1, 9)

\int arccot (10 x) d x

\frac{\partial}{\partial y} (e^{(x + y)})

What is the integral of (sin(x))/3 ?
The integral of (sin(x))/3 is -1/3 cos(x)+C