What is (\partial)/(\partial x)(5cos(7x-3y)) ?

The answer to (\partial)/(\partial x)(5cos(7x-3y)) is -35sin(7x-3y)

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(\partial)/(\partial x)(5cos(7x-3y))

\frac{\partial}{\partial x} (5 cos (7 x - 3 y))

- 35 sin (7 x - 3 y)

Solution steps

\frac{\partial}{\partial x} (5 cos (7 x - 3 y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{\partial}{\partial x} (cos (7 x - 3 y))

Apply the chain rule:

- sin (7 x - 3 y) \frac{\partial}{\partial x} (7 x - 3 y)

= - sin (7 x - 3 y) \frac{\partial}{\partial x} (7 x - 3 y)

\frac{\partial}{\partial x} (7 x - 3 y) = 7

= 5 (- sin (7 x - 3 y) \cdot 7)

Simplify

= - 35 sin (7 x - 3 y)

x \to 2 + lim (\frac{1}{∣ 2 - x ∣})

f (x) = (3 x^{6} + 8 x^{3})^{4}

\frac{d}{d x} (\frac{1}{x ^{2} + a ^{2}})

\frac{5}{s ^{8}}

x \to 1 lim (i n^{4} x + e^{x})

What is (\partial)/(\partial x)(5cos(7x-3y)) ?
The answer to (\partial)/(\partial x)(5cos(7x-3y)) is -35sin(7x-3y)