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Popular >

y^'=-(2xy)/(1+x^2)

Solution

y^{^{'}} = - \frac{2 x y}{1 + x ^{2}}

Solution

y = \frac{c _{1}}{1 + x ^{2}}

Solution steps

y^{'} (x) = - \frac{2 x y}{1 + x ^{2}}

Solve separable ODE:

y = \frac{c _{1}}{1 + x ^{2}}

y = \frac{c _{1}}{1 + x ^{2}}

Popular Examples

f (z) = \frac{1}{z}

integral of 25t^4e^{-t^5}

\int 25 t^{4} e^{- t^{5}} d t

limit as x approaches 13 of pi

x \to 13 lim (π)

derivative of 10x^{3/2}

\frac{d}{d x} (10 x^{\frac{3}{2}})

integral from 1 to 2 of 8/(x^2-2x+2)

\int_{1}^{2} \frac{8}{x ^{2} - 2 x + 2} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=-(2xy)/(1+x^2) ?
The solution for y^'=-(2xy)/(1+x^2) is y=(c_{1})/(1+x^2)