What is the solution for yy^'-6e^x=0 ?

The solution for yy^'-6e^x=0 is y=sqrt(12e^x+c_{1)},y=-sqrt(12e^x+c_{1)}

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yy^'-6e^x=0

y y^{^{'}} - 6 e^{x} = 0

y = 12 e^{x} + c_{1}, y = - 12 e^{x} + c_{1}

Solution steps

y y^{'} (x) - 6 e^{x} = 0

Solve separable ODE:

y = 12 e^{x} + c_{1}, y = - 12 e^{x} + c_{1}

y = 12 e^{x} + c_{1}, y = - 12 e^{x} + c_{1}

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x \to \frac{x}{4} lim (\frac{sin ( x )}{x})

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What is the solution for yy^'-6e^x=0 ?
The solution for yy^'-6e^x=0 is y=sqrt(12e^x+c_{1)},y=-sqrt(12e^x+c_{1)}