What is the sum from n=0 to infinity of (n^3)/(3^n) ?

The sum from n=0 to infinity of (n^3)/(3^n) is converges

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sum from n=0 to infinity of (n^3)/(3^n)

n = 0 \sum \infty \frac{n ^{3}}{3 ^{n}}

converges

Solution steps

n = 0 \sum \infty \frac{n ^{3}}{3 ^{n}}

Apply Series Ratio Test:

converges

= converges

\frac{d}{d x} ((\frac{x ^{3}}{9})^{2})

\frac{\partial}{\partial y} (\frac{1}{y})

x \to 1 lim (cos (\frac{1}{x - 1}))

y^{^{''}} - 2 y^{^{'}} = 7 t

\frac{\partial}{\partial x} (x^{0.5} \cdot y^{0.5} \cdot z)

What is the sum from n=0 to infinity of (n^3)/(3^n) ?
The sum from n=0 to infinity of (n^3)/(3^n) is converges