What is the solution for (dx}{dt}=\frac{4x)/t ,x(1)=1 ?

The solution for (dx}{dt}=\frac{4x)/t ,x(1)=1 is x=t^4

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(dx}{dt}=\frac{4x)/t ,x(1)=1

\frac{d x}{d t} = \frac{4 x}{t}, x (1) = 1

x = t^{4}

Solution steps

\frac{d x}{d t} = \frac{4 x}{t}

Solve separable ODE:

x = t^{4}

x = t^{4}

\int \frac{e ^{2 x} ( 1 + 2 x ln ( x ) )}{4 x} d x

\int \frac{x}{( 4 - x ^{2} ) ^{2}} d x

\frac{4 x}{x + 1}

\int_{1}^{1.5} (\frac{1}{8} + \frac{3}{8} x) d x

f (t) = 4 t^{2} - 5 sin (3 t)

What is the solution for (dx}{dt}=\frac{4x)/t ,x(1)=1 ?
The solution for (dx}{dt}=\frac{4x)/t ,x(1)=1 is x=t^4