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Popular >

derivative of f(t)=e^{9tsin(2t)}

Solution

derivative of

f (t) = e^{9 t s i n (2 t)}

Solution

e^{9 t s i n (2 t)} \cdot 9 (sin (2 t) + 2 t cos (2 t))

Solution steps

\frac{d}{d t} (e^{9 t s i n (2 t)})

Apply the chain rule:

e^{9 t s i n (2 t)} \frac{d}{d t} (9 t sin (2 t))

= e^{9 t s i n (2 t)} \frac{d}{d t} (9 t sin (2 t))

\frac{d}{d t} (9 t sin (2 t)) = 9 (sin (2 t) + 2 t cos (2 t))

= e^{9 t s i n (2 t)} \cdot 9 (sin (2 t) + 2 t cos (2 t))

Popular Examples

y^{''}+49y=sec^2(7x)

y^{^{''}} + 49 y = sec^{2} (7 x)

derivative of (x^2)/(x+8)derivative of

\frac{x ^{2}}{x + 8}

(\partial)/(\partial x)(x^3y^2+2x^2y+x-1)

\frac{\partial}{\partial x} (x^{3} y^{2} + 2 x^{2} y + x - 1)

integral of 3sec^{-2}(xta)n^3x

\int 3 sec^{- 2} (x t a) n^{3} x d x

limit as x approaches 9 of 2x^2-3

x \to 9 lim (2 x^{2} - 3)

Frequently Asked Questions (FAQ)

What is the derivative of f(t)=e^{9tsin(2t)} ?
The derivative of f(t)=e^{9tsin(2t)} is e^{9tsin(2t)}*9(sin(2t)+2tcos(2t))
What is the first derivative of f(t)=e^{9tsin(2t)} ?
The first derivative of f(t)=e^{9tsin(2t)} is e^{9tsin(2t)}*9(sin(2t)+2tcos(2t))