What is the derivative of 8x-2x^2 ?

The derivative of 8x-2x^2 is 8-4x

What is the first derivative of 8x-2x^2 ?

The first derivative of 8x-2x^2 is 8-4x

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\frac{d}{d x} (8 x - 2 x^{2})

8 - 4 x

Solution steps

\frac{d}{d x} (8 x - 2 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 x) - \frac{d}{d x} (2 x^{2})

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (2 x^{2}) = 4 x

= 8 - 4 x

\frac{x ^{2}}{2}

f (x) = (x + 8)^{3 x}

sin^{2} (x), sin^{4} (x)

x \to - 6 lim (36 - x^{2})

\frac{\partial}{\partial y} (x y + x^{4} + y^{4})

What is the derivative of 8x-2x^2 ?
The derivative of 8x-2x^2 is 8-4x
What is the first derivative of 8x-2x^2 ?
The first derivative of 8x-2x^2 is 8-4x