What is the derivative of (x-4/x) ?

The derivative of (x-4/x) is 4/(x^2)

What is the first derivative of (x-4/x) ?

The first derivative of (x-4/x) is 4/(x^2)

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\frac{d}{d x} (\frac{x - 4}{x})

\frac{4}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{x - 4}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x - 4 ) x - \frac{d x}{d x} ( x - 4 )}{x ^{2}}

\frac{d}{d x} (x - 4) = 1

\frac{d x}{d x} = 1

= \frac{1 \cdot x - 1 \cdot ( x - 4 )}{x ^{2}}

Simplify

\frac{1 \cdot x - 1 \cdot ( x - 4 )}{x ^{2}} : \frac{4}{x ^{2}}

= \frac{4}{x ^{2}}

n = 1 \sum \infty \frac{1}{4 n}

\frac{d}{d x} (x^{3} - \frac{3 x ^{2}}{2})

\int \frac{1}{20} x d x

y^{^{'}} = 2 y^{2} sin (x)

(t - 2)^{2}

What is the derivative of (x-4/x) ?
The derivative of (x-4/x) is 4/(x^2)
What is the first derivative of (x-4/x) ?
The first derivative of (x-4/x) is 4/(x^2)