What is (\partial)/(\partial x)(-sin(x)y) ?

The answer to (\partial)/(\partial x)(-sin(x)y) is -ycos(x)

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(\partial)/(\partial x)(-sin(x)y)

\frac{\partial}{\partial x} (- sin (x) y)

- y cos (x)

Solution steps

\frac{\partial}{\partial x} (- sin (x) y)

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - y \frac{\partial}{\partial x} (sin (x))

Apply the common derivative:

\frac{\partial}{\partial x} (sin (x)) = cos (x)

= - y cos (x)

\int \frac{1}{π x ( 1 - x )} d x

\int \frac{x ^{2}}{( x - 5 ) ^{3}} d x

\frac{d}{d x} (cos (2 - 7 x))

\frac{x}{5 - x}

f (x) = (2 x - 8)^{4} (x^{2} + x + 1)^{5}

What is (\partial)/(\partial x)(-sin(x)y) ?
The answer to (\partial)/(\partial x)(-sin(x)y) is -ycos(x)